(xy^2)dy-(x^3+y^3)xD=0

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Solution for (xy^2)dy-(x^3+y^3)xD=0 equation: 


Simplifying
(xy2) * dy + -1(x3 + y3) * xD = 0

Multiply xy2 * dy
dxy3 + -1(x3 + y3) * xD = 0

Reorder the terms for easier multiplication:
dxy3 + -1xD(x3 + y3) = 0
dxy3 + (x3 * -1xD + y3 * -1xD) = 0

Reorder the terms:
dxy3 + (-1xy3D + -1x4D) = 0
dxy3 + (-1xy3D + -1x4D) = 0

Solving
dxy3 + -1xy3D + -1x4D = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add 'xy3D' to each side of the equation.
dxy3 + -1xy3D + xy3D + -1x4D = 0 + xy3D

Combine like terms: -1xy3D + xy3D = 0
dxy3 + 0 + -1x4D = 0 + xy3D
dxy3 + -1x4D = 0 + xy3D
Remove the zero:
dxy3 + -1x4D = xy3D

Add 'x4D' to each side of the equation.
dxy3 + -1x4D + x4D = xy3D + x4D

Combine like terms: -1x4D + x4D = 0
dxy3 + 0 = xy3D + x4D
dxy3 = xy3D + x4D

Divide each side by 'xy3'.
d = D + x3y-3D

Simplifying
d = D + x3y-3D

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